Linear Equations in Two Variables: Solutions for practice set 1.1 of Maharashtra State Board for Maths 1 Algebra 10th Standard. 



PRACTICE SET 1.1


Q.1) Complete the following activity to solve the simultaneous equations.

5x + 3y = 9

2x - 3y = 12

SOLUTION :-

5x +3y = 9------(1)
2x - 3y = 12------(2)

Adding equations (1) & (2)

5x + 3y = 9
2x - 3y = 12
7x - 0   = 21

x = 21
       7
x = 3

Putting the value of x = 3 in equation (1) we get

5x + 3y = 9------(1)
5(3) + 3y = 9
15 + 3y = 9
3y = 9 - 15
3y = -6
y = -6
       3
y = -2

Thus, (x,y) = (3,-2)


Q.2) Solve the following simultaneous equation.

3a + 5b = 26
a + 5b = 22

SOLUTION :-

3a + 5b = 26-----(1)
a + 5b = 22-------(2)

Subtracting (2) from (1)

3a + 5b = 26
a + 5b = 22
2a = 4

a = 4/2
a = 2

Putting the value of  a = 2 in eq (2)

a + 5b = 22-----(2)

2 + 5b = 22
5b = 22 - 2
5b = 20
b = 20/5
b = 4 

Thus, (a,b) = (2,4)


Q.3) Solve the following simultaneous equation.

x + 7y = 10
3x - 2y = 7

SOLUTION :-
 
x + 7y = 10-----(1)
3x - 2y = 7------(2)

Multiply equation (1) by 3,

3x + 21y = 30-----(3)

Subtracting eq (2) from (3) ,we get,

3x + 21y = 30
3x - 2y = 7     
0 + 23y = 23

23y = 23
y = 23/23
y = 1

Putting the value of y = 1 in eq (2), we get,

3x - 2y = 7

3x -2(1) = 7
3x - 2 = 7
3x = 7 + 2
3x = 9
x = 9/3
x = 3

Thus, (x,y) = (3,1).


Q.4) Solve the following simultaneous equation.

2x - 3y = 9
2x + y = 13

SOLUTION :-

2x - 3y = 9------(1)
2x + y = 13-----(2)

Subtracting eq (1) from (2) ,we get,
       
2x - 3y = 9
2x + y = 13
0 - 4y = -4

-4y = -4
y = -4/-4
y = 1

Substitute y = 1 in eq (2)

2x + y = 13

2x + 1 = 13
2x = 13 - 1
2x = 12
x = 12/2
x = 6

Thus, (x,y) = (6,1).


Q.5) Solve the following simultaneous equation.

5m - 3n = 19
m - 6n = -7

SOLUTION :-

5m - 3n = 19----(1)
m - 6n = -7------(2)

Multiply eq (1) by 2, we get,

10m - 6n = 38----(3)

Subtracting eq (2) from (3) ,we get,

10m - 6n = 38
m - 6n = -7     
9m = 45
m = 45/9
m = 5

Putting the value of m = 5 in eq (2), we get,

m - 6n = -7
5 - 6n = -7
-6n = -7 - 5
-6n = -12
n = -12/-6
n = 2


Thus, (m,n) = (5, 2).


Q.6) Solve the following simultaneous equation.

5x + 2y = -3
x + 5y = 4

SOLUTION :-

5x + 2y = -3-----(1)
x + 5y = 4--------(2)

Multiply (2) with 5 we get,

5x + 25y = 20-----(3)

Subtracting  eq (3) from (1) we get,


5x + 2y = -3
5x + 25y = 20
0 - 23y = -23

-23y = -23
y = -23/-23
y = 1

Putting the value of y = 1 in eq (2) we get,

x + 5y = 4
x + 5(1) = 4
x + 5 = 4
x = 4 - 5
x= -1

 Thus, (x,y) = (-1, 1).


Q.7) Solve the following simultaneous equation.

 1/3x + y =10/3

2x + 1/4y = 11/4


SOLUTION :-

 1/3x + y = 10/3-----(1)

2x + 1/4y = 11/4---(2)

Multiply (1) with 3 & (2) with 4

x + 3y = 10----(3)

8x + y = 11----(4)

Multiply (4) with 3

24x + 3y = 33----(5)

Subtracting eq (5) from (3)

x + 3y = 10 

24x + 3y = 3

 - 23x = -23

x = -23/-23

x = 1

Putting the value of x = 1 in eq (3)

x + 3y = 10

1 + 3y = 10

3y = 10 - 1

3y = 9

y = 9/3

y = 3

 Thus, (x,y) = (1, 3).


Q.7) Solve the following simultaneous equation.

99x + 101y = 499

101x + 99y = 501


SOLUTION :-

99x + 101y = 499----(1)

101x + 99y = 501----(2)

Adding (1) and (2)

200x + 200y = 1000---(3)

divide eq (3) with 200

x + y = 5-----(4)

Subtracting (1) from (2), we get,

2x - 2y = 2----(5)

 divide eq (5) with 2

x - y = 1----(6)

Adding eq (4) & (6)

x + y = 5

x - y = 1 

2x = 6

x = 6/2

x = 3

Putting the value of  x = 3 in eq (6)

x - y = 1

3 - y = 1

y = 2


 Thus, (x,y) = (3, 2).


Q.8) Solve the following simultaneous equation.

49x - 57y = 172

57x - 49y = 252


SOLUTION :-

49x - 57y = 172----(1)

57x - 49y = 252----(2)

Adding (1) and (2)

(49x + 57y) + (-57y-49) = 172 + 252

106x +(-106y) =424

106(x-y) =424

(x-y) = 424/106

x-y =4----(3)

Subtracting (2) from (1)

(57x - 49x) + [-49-(-57y)]=252-172

8x +(-49y+57y) = 80

8x + 8y =80

8(x+y) = 80

x + y = 80/8

x + y = 10----(4)

Adding (3) and (4)

x+x-y+y=4+10

2x =14

x= 7

putting the value of x = 7 in eq (4) 

x +y =10

7+y=10

y=10-7

y=3

Thus, (x,y) = (7,3).